Answer
$\frac{6p-30}{3p-15}=2; p \ne 5$
Work Step by Step
Given: $\frac{6p-30}{3p-15}$
Consider denominator $(3p-15)=0$ to check the exclude value which makes the denominator $0$.
$3p=15$
$p=\frac{15}{3}$
Thus, $p=5$
$\frac{6p-30}{3p-15} = \frac{6(p-5)}{3(p-5)}$
Hence, $\frac{6p-30}{3p-15}=2; p \ne 5$
