Answer
$\dfrac{7b^2+6b-4}{3b(b+2)}$
Work Step by Step
As we are given that $\frac{4b-2}{3b}+\frac{b}{b+2}$
LCD $= 3b(b+2)$
$=\dfrac{4b-2(b+2)}{3b(b+2)}+\dfrac{(3b)b}{3b(b+2)}$
After simplifications, we get
$=\dfrac{(4b-2)(b+2)+b(3b)}{3b(b+2)}$
$=\dfrac{4b^2+8b-2b-4+3b^2}{3b(b+2)}$
$=\dfrac{7b^2+6b-4}{3b(b+2)}$
