Answer
$\dfrac{(x+2)}{4}$
Work Step by Step
As we are given that $\dfrac{3}{(x-2)} \times \dfrac {x^2-4}{12}$
As we know $a^2-b^2=(a-b)(a+b)$
Thus, $\dfrac{3}{(x-2)} \times \dfrac {x^2-4}{12}=\dfrac{3(x-2)(x+2)}{12(x-2)}$
$=\dfrac{(x+2)}{4}$