Answer
$x=6$
Work Step by Step
Given: $(x+2)(x-1)=(x-2)(x+4)$
$x^2-x+2x-2=x^2+4x-2x-8$
$x^2+4x-2x-8-x^2+x-2x+2=0$
$2x-8+x-2x+2=0$
$x-6=0$
Hence, $x=6$
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