Answer
$c=1, 4$
Work Step by Step
Given: $c=c(c-2)-2(c-2)$
$\frac{c}{c}=\frac{c(c-2)}{c}-\frac{2(c-2)}{c}$
$\implies 1=(c-2)-\frac{2(c-2)}{c}$
$\implies 1=(c-2)-\frac{2(c-2)}{c}$
or, $c^2-5c+4=0$
Thus, $(c-4)(c-1)=0 \implies c=1, 4$