Answer
$m=-\frac{3}{2}, 4$
Work Step by Step
Given: $3(m+4)=2m(m-1)$
$3m+12=2m^2-2m$
$2m^2-2m-3m-12=0$
$2m^2-5m-12=0$
$2m^2+8m-3m-12=0$
$(2m+3)(m-4)=0$
Solutions are: $2m+3=0 \implies m=-\frac{3}{2}$,
and $m-4=0 \implies m=4$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 683: 27
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