Answer
$x=1,3$
Work Step by Step
Given: $8x=(x+3)+(x^2+3x)$
$8x=x+3+x^2+3x$
$\implies x^2+4x+3=8x$
$\implies x^2+4x+3-8x=0$
$\implies x^2-4x+3=0$
$\implies (x-3)(x-1)=0$
Solutions are: $x=1,3$
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