Answer
$121$
Work Step by Step
$z^2+22z+c$
Compare it with $az^2+bz+c$, we have $b=18$
For perfect-square trinormal add $(\frac{b}{2})^2$ and Plug $b=22$ to complete the square.
$c=(\frac{22}{2})^2=(11)^2=121$
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