Answer
$\frac{289}{4}$
Work Step by Step
$g^2+17g+c$
Compare it with the standard form of quadratic equation $ax^2+bx+c$, we have $a=1, b=17$
It will have discriminant, $d$ with formula : $d=b^2-4ac$
Since, $d=0$ for repeated root of the expression.
Therefore, $b^2=4ac$ $\implies$ $c=\dfrac{b^2}{4a}$
To complete the square, plug in $a=1, b=17$.
Thus, $c=\dfrac{b^2}{4a}=\dfrac{(17)^2}{4}=\frac{289}{4}$
