Answer
$w=13,1$
Work Step by Step
$w^2-14w+13=0$
or, $w^2-14w=-13$
Compare it with the standard form of quadratic equation $ax^2+bx+c$, we have $a=1, b=-14$
Therefore, $b^2=4ac$ $\implies$ $c=\dfrac{b^2}{4a}$
Thus, $c=\dfrac{b^2}{4a}=\dfrac{(-14)^2}{4}=49$
To complete the square, add $4$ on both sides.
$w^2-14w+49=-13+49$
$\implies (w-7)^2=36$
$\implies w-7=6$
and
$\implies w-7=-6$
or, $w=13,1$
