Answer
$\boxed{\frac{q^6}{p^5}}$
Work Step by Step
First, we can get rid of $m^2$ from both the numerator and the denominator.
$\frac{p^{-3}q^{4}}{p^2q^{-2}}$
$\frac{p^{-3}}{q^{-2}}$ is the same as $\frac{q^2}{p^3}$.
$\frac{q^2q^4}{p^2p^3}$
$\boxed{\frac{q^6}{p^5}}$
