Answer
$g=-\frac{1}{2}$ or $g=\frac{5}{3}$
Work Step by Step
$6g^2-7g=5$
$6g^2-7g-5=0$
$6g^2-10g+3g-5=0$
$2g(3g-5)+(3g-5)=0$
$(2g+1)(3g-5)=0$
$2g+1=0$ or $3g-5=0$
$2g=-1$ or $3g=5$
$g=-\frac{1}{2}$ or $g=\frac{5}{3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 17
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