Answer
$y=\frac{-5}{3}$ or $y=\frac{7}{4}$
Work Step by Step
$12y^2-y=35$
$12y^2-y-35=0$
$12y^2-21y+20y-35=0$
$3y(4y-7)+5(4y-7)=0$
$(3y+5)(4y-7)=0$
$3y+5=0$ or $4y-7=0$
$y=\frac{-5}{3}$ or $y=\frac{7}{4}$
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