Answer
$r=-5$ or $r=-\frac{2}{3}$
Work Step by Step
$6r^2+20=-34r$
$6r^2+34r+20=0$
$6r^2+4r+30r+20=0$
$2r(3r+2)+10(3r+2)=0$
$(2r+10)(3r+2)=0$
$2r+10=0$ or $3r+2=0$
$2r=-10$ or $3r=-2$
$r=-5$ or $r=-\frac{2}{3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 14
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