Answer
$ \frac{-21t+33}{2t-3}$
Work Step by Step
Given : $\frac{t}{2t-3} - 11= \frac{t}{2t-3}+\frac{-11(2t-3)}{2t-3}$
This becomes : $\frac{t-11(2t-3)}{2t-3}$
(Since they both have the same denominator)
$= \frac{-21t+33}{2t-3}$
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