Answer
$ \frac{a^{2}+12a+15}{4(a+3)}$
Work Step by Step
Given : $\frac{a}{a+3} + \frac{a+5}{4}$
This becomes : $\frac{a\times4}{4(a+3)} + \frac{(a+5)(a+3)}{4(a+3)}$
$= \frac{4a+a^{2}+3a+5a+15}{4(a+3)}$
$= \frac{a^{2}+12a+15}{4(a+3)}$
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