Answer
$ \frac{10x+15}{x+2}$
Work Step by Step
Given : $9 + \frac{x-3}{x+2}= \frac{9(x+2)}{x+
2}+\frac{x-3}{x+2}$
This becomes : $\frac{9(x+2)+x-3}{x+2}$
(Since they both have the same denominator)
$= \frac{10x+15}{x+2}$
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