Answer
$ \frac{r-2k-6}{9+p^{3}}$
Work Step by Step
Given : $\frac{r-5}{9+p^{3}} - \frac{2k+1}{9+p^{3}}$
This becomes : $\frac{r-5-(2k+1)}{9+p^{3}}$
(Since they both have the same denominator)
$= \frac{r-2k-6}{9+p^{3}}$
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