Answer
The answer is $2r^4+r^2-7$
Work Step by Step
$(21-5r^4-10r^2+2r^6) \div (r^2-3)$
$=(2r^6-5r^4-10r^2+21) \div (r^2-3)$
$-16c^2-20c-25$
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$r^2-3) 2r^6-5r^4-10r^2+21$
$-2r^6+6r^4$
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$r^4-10r^2$
$-r^4+3r^2$
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$-7r^2 +21$
$-7r^2 +21$
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$0$
The answer is $2r^4+r^2-7$.