Answer
The answer is $k^2-0.3k-0.4$.
Work Step by Step
$(3k^3-0.9k^2-1.2k) \div 3k$
$=\frac{3k^3}{3k}-\frac{0.9k^2}{3k}-\frac{1.2k}{3k}$
$=k^2-0.3k-0.4$
The answer is $k^2-0.3k-0.4$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 682: 40
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