Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 682: 42

The answer is $-16c^2-20c-\frac{25}{5-4c}$

$(64c^3-125) \div (5-4c)$ $=(64c^3-125) \div (-4c+5)$ $-16c^2-20c-25$ _________________________ $5-4c) 64c^3-125$ $-64c^3+80c^2$ _________________________ $80c^2-125 $ $-80c^2+100$ _________________________ $-25$ The answer is $-16c^2-20c-\frac{25}{5-4c}$