Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 676: 64

$\frac{x+2}{4(x+7)}, with$ $x\ne-7$

Given : $\frac{x-5}{3x+2} \times \frac{3x+2}{4} \times \frac{x+2}{x^{2}+2x-35}$ This becomes : $\frac{x-5}{3x+2} \times \frac{3x+2}{4} \times \frac{x+2}{(x+7)(x-5)}$ $= \frac{x+2}{4(x+7)}$ (After dividing out the common factors (x-5) and (3x+2))