Answer
When $x = 0$ and $x=-4$ the expression is undefined.
Work Step by Step
$\frac{2x^2-5x-12}{6x} \div \frac{-3x-12}{x^2-16} $
Solve for what x cannot be:
$6x = 0 \rightarrow x = 0$
$-3x-12 = 0 \rightarrow x =-4$
When $x = 0$ and $x=-4$ the expression is undefined.