Answer
$ -3n^{2} + 11n + 20$
Work Step by Step
Given : $(-3n-4)(n-5)$
This becomes : $-3n(n) -3n(-5)-4(n)-4(-5)$
(After distributing)
$= -3n^{2} + 15n - 4n + 20$
$= -3n^{2}+11n+20$
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