Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 676: 78

Answer

$ -3n^{2} + 11n + 20$

Work Step by Step

Given : $(-3n-4)(n-5)$ This becomes : $-3n(n) -3n(-5)-4(n)-4(-5)$ (After distributing) $= -3n^{2} + 15n - 4n + 20$ $= -3n^{2}+11n+20$
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