Answer
$\frac{2x}{x-2}, with$ $x\ne2$
Work Step by Step
Given : $(2x-5) \times \frac{2x}{2x^{2}-9x-10}$
This becomes : $(2x-5) \times \frac{2x}{(2x-5)(x-2)}$
$= \frac{2x}{x-2}$
(After dividing out the common factor (2x-5))
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