University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 298: 9.66

Answer

$t=0.432 s$ $ \alpha=67.6 rad/s^2$

Work Step by Step

$\theta$=$\theta0-\omega0*\alpha/2*t^2$ $4*\Pi=\alpha/2*(0.610)^2$ $==> \alpha=67.6 rad/s^2$ a) $2*\Pi=\alpha/2*t^2$ $==> t=0.431$s
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.