University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 298: 9.65

Answer

The radius of the rear sprocket is 2.99 cm.

Work Step by Step

We can find the angular speed of the rear sprocket. Let $v_r$ be the tangential speed of the rear wheel. $\omega = \frac{v_r}{r} = \frac{5.00~m/s}{0.330~m}$ $\omega = 15.15~rad/s$ We can find the tangential speed of the rear sprocket. Let $\omega_f$ be the angular speed of the front sprocket. $v = \omega_f ~r$ $v = (0.600~rev/s)(2\pi~rad/rev)(0.120~m)$ $v = 0.4524~m/s$ We can find the radius of the rear sprocket. $r = \frac{v}{\omega} - \frac{0.4524~m/s}{15.15~rad/s}$ $r = 0.0299~m = 2.99~cm$ The radius of the rear sprocket is 2.99 cm.
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