University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 267: 8.59

Answer

$F_x = (-1.5~kg~m/s^3)~t$ $F_y = (0.25~kg~m/s^2)$ $F_z = 0$

Work Step by Step

$p = [(-0.75~kg~m/s^3)~t^2+(3.0~kg~m/s)]~\hat{i}+(0.25~kg~m/s^2)~t~\hat{j}$ $F = \frac{dp}{dt} = [(-1.5~kg~m/s^3)~t]~\hat{i}+(0.25~kg~m/s^2)~\hat{j}$ $F_x = (-1.5~kg~m/s^3)~t$ $F_y = (0.25~kg~m/s^2)$ $F_z = 0$
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