University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 267: 8.51

Answer

The coordinates of the center of mass are: (0.0444 m, 0.0555 m)

Work Step by Step

$x_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}$ $x_{cm} = \frac{(0.300~kg)(0.200~m)+(0.400~kg)(0.100~m)+(0.200~kg)(-0.300~m)}{0.300~kg+0.400~kg+0.200~kg}$ $x_{cm} = 0.0444~m$ $y_{cm} = \frac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3}$ $y_{cm} = \frac{(0.300~kg)(0.300~m)+(0.400~kg)(-0.400~m)+(0.200~kg)(0.600~m)}{0.300~kg+0.400~kg+0.200~kg}$ $y_{cm} = 0.0555~m$ The coordinates of the center of mass are: (0.0444 m, 0.0555 m)
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