University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 7 - Potential Energy and Energy Conservation - Problems - Exercises - Page 233: 7.64

Answer

The maximum distance that the spring stretches is 2d.

Work Step by Step

We can find the force constant of the spring. $kd = mg$ $k = \frac{mg}{d}$ We can use the spring constant to find the maximum distance $y$ that the spring stretches. $U_s = U_g$ $\frac{1}{2}ky^2 = mgy$ $\frac{1}{2}(\frac{mg}{d})y^2 = mgy$ $y = 2d$ The maximum distance that the spring stretches is 2d.
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