Answer
50 N.
Work Step by Step
Apply Newton’s second law to the 2-box system.
$\Sigma F_x=ma_x$
$250N=(25.0 kg)a$
$a=10.0m/s^2$
Now consider box B.
$F_{A\;on\;B}=m_Ba=(5.0kg)(10.0m/s^2)=50N$
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