University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 4 - Newton's Laws of Motion - Problems - Exercises - Page 125: 4.22

Answer

The upward normal force exerted by the floor on the passenger is 620 N. The reaction force is the downward force of 620 N exerted by the passenger on the floor. The weight of the passenger is 650 N. The reaction force is the gravitational force of 650 N pulling upward on the earth. The passenger is accelerating downward with a magnitude of $a = 0.452~m/s^2$

Work Step by Step

The upward normal force exerted by the floor on the passenger is 620 N. The reaction force is the downward force of 620 N exerted by the passenger on the floor. The weight of the passenger is 650 N. The reaction force is the gravitational force of 650 N pulling upward on the earth. We can find the mass of the passenger. $mg = 650~N$ $m = \frac{650~N}{9.80~m/s^2} = 66.33~kg$ We can find the passenger's acceleration. $\sum F = ma$ $mg-F_N = ma$ $a = \frac{650~N-620~N}{66.33~kg} = 0.452~m/s^2$ The passenger is accelerating downward with a magnitude of $a = 0.452~m/s^2$
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