Answer
b) a_{av,x}=-8.67m/s
a_{av,y}=-2.33m/s
c)a= 8.98m/s^{s}
angle = 195^{\circ}
Work Step by Step
b) a_{av,x}=change in v in x-direction/change in time= (-170-90)/30=-8.67m/s
a_{av,y}= 40-110/30=-2.33m/s
c)a=\sqrt ((-8.667^{2})+ (-2.333^{2})) = 8.98m/s^{s}
tan \theta= a_{av,y}/a_{av,x = 0.269
\theta = 15^{\circ}
Therefore, the angle is 180+15 = 195^{\circ}, since the components are in the third quadrant
