Answer
(a) $\tau = 2.56~N~m$
(b) $\tau = 4.25~N~m$
The machinist could exert the maximum torque when the force is applied at the end of the wrench at an angle of $90^{\circ}$
Work Step by Step
(a) $\tau = r~F~sin(\theta)$
$\tau = (0.250~m)(17.0~N)~sin(37^{\circ})$
$\tau = 2.56~N~m$
(b) The machinist could exert the maximum torque when the force is applied at the end of the wrench at an angle of $90^{\circ}$
$\tau = r~F~sin(\theta)$
$\tau = (0.250~m)(17.0~N)~sin(90^{\circ})$
$\tau = 4.25~N~m$
