Answer
The net torque is -0.310 N m
Work Step by Step
$\sum \tau = \tau_1+\tau_2+\tau_3$
$\sum \tau = F_1~r_1~sin(\theta_1)-F_2~r_2~sin(\theta_2)+F_3~r_3~sin(\theta_3)$
$\sum \tau = (11.9~N)(0.350~m)~sin(180^{\circ})-(14.6~N)(0.350~m)~sin(40.0^{\circ})+(8.50~N)(0.350~m)~sin(90.0^{\circ})$
$\sum \tau = -0.310~N~m$
The net torque is -0.310 N m.
