University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 29: 1.47

Answer

(a) Magnitude = 63.9 $m^{2}$ in the - z direction. (B) Magnitude = 63.9 $m^{2}$ in the z direction.

Work Step by Step

(a) Given : From the given Diagram |A|= 8 m And |D|= 20 m So, The angle Between A and D =∅ =90 +(90-53) = 120∘ Magnitude = |A×B| = AB sin ∅ (a) Magnitude =8×10×sin(127) =63.9 $m^{2}$ Therefore, By the right-hand rule, the direction is -z (b) D×A has the same magnitude but in the opposite direction (z) because of A×B= −D×A
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