University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 29: 1.45

Answer

(a) $164. 75^{\circ}$ (b) $28.07^{\circ}$ c)$90.0^{\circ}$

Work Step by Step

(a) cos φ=$ \frac{AxBx+AyBy}{AB}$ =$\frac{(-2.00) (2.00)+(6.00)(-3.00)}{(\sqrt (-2.00)^{2}+\sqrt (6.00)_{y} (\sqrt (2.00)^{2}+\sqrt (-3.00)^{2}}$ =-0.964764 -> φ = $164. 75^{\circ}$ (b) cos φ=$ \frac{AxBx+AyBy}{AB}$ =$\frac{(3.00) (10.00)+(5.00)(6.00)}{(\sqrt (3.00)^{2}+\sqrt (5.00)_{y} (\sqrt (10.00)^{2}+\sqrt (6.00)^{2}}$ =0.882353 -> φ = $28.07^{\circ}$ (c) cos φ=$ \frac{AxBx+AyBy}{AB}$ =$\frac{(-4.00) (7.00)+(2.00)(14.00)}{(\sqrt (-4.00)^{2}+\sqrt (2.00)_{y} (\sqrt (7.00)^{2}+\sqrt (14.00)^{2}}$ =0 -> φ = $90^{\circ}$
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