Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 50: 1-121

Answer

d) $204m$

Work Step by Step

Knowing that: $P=\rho gh$ $\Delta P=98kPa-96kPa=2kPa$ $h=\frac{\Delta P}{\rho g}=\frac{2000Pa}{1.0\frac{kg}{m^3}*9.81\frac{m}{s^2}}$ $h=203.87m$
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