Answer
b) $2.50kJ$
Work Step by Step
Knowing that:
Drop $1^{\circ}C$ corresponds to $1.8^{\circ}F$
Then:
$\frac{4.5kJ}{1^{\circ}C}*\frac{1^{\circ}C}{1.8^{\circ}F}=2.50\frac{kJ}{^{\circ}F}$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 1 - Introduction and Basic Concepts - Problems - Page 50: 1-119
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