Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 49: 1-108

Answer

$h=1.12m$

Work Step by Step

First we calculate the $P_{gage}$ $P_{gage}=P_{abs}-P_{atm}=110kPa-99kPa=11kPa$ This pressure will be equal to: $P_{gage}=\rho_{water}gh$ Solving for $h$: $h=\frac{P_{gage}}{\rho_{water}g}=\frac{11000}{1000\frac{kg}{m^3}*9.81\frac{m}{s^2}}=1.12m$
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