Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 49: 1-106

Answer

$m=20.39kg$

Work Step by Step

First we calculate the piston pression: $P=P_{abs}-P_{atm}=180kPa-100kPa=80kPa$ Area of piston will be: $25cm^2*\frac{1m^2}{10000cm^2}=0.0025m^2$ The force make by the piston is: $F=PA=80000Pa*0.0025m^2=200N$ And the mass of the piston is: $m=\frac{F}{g}=\frac{200N}{9.81\frac{m}{s^2}}=20.39kg$
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