Answer
$T_{atmospheric}(^{\circ}C) = -63$
Work Step by Step
$T_{atmospheric} = 288.15 - 6.5z$
$T_{atmospheric} = 288.15-6.5\times 12$
$T_{atmospheric} = 210.15 K$
$T_{atmospheric}(^{\circ}C) = 210.15 - 273.15 = -63$
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