Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 47: 1-90E

Answer

$9.81N=0.00981kN=9.81\frac{kg*m}{s^2}=1kgf=71\frac{lbm*ft}{s^2}=2.21lbf$

Work Step by Step

Knowing that: $W=mg$ $W=1kg*9.81\frac{m}{s^2}*\frac{1N}{1\frac{kg*m}{s^2}}=9.81N$ $W=1kg*9.81\frac{m}{s^2}*\frac{1kN}{1000\frac{kg*m}{s^2}}=0.00981kN$ $W=1kg*9.81\frac{m}{s^2}=9.81\frac{kg*m}{s^2}$ $W=1kg*9.81\frac{m}{s^2}*\frac{1N}{1\frac{kg*m}{s^2}}*\frac{1kgf}{9.81N}=1kgf$ $1kg*\frac{2.205lbm}{1kg}=2.205lbm$ $W=2.205lbm*32.2\frac{ft}{s^2}=71\frac{lbm*ft}{s^2}$ $W=2.205lbm*32.2\frac{ft}{s^2}*\frac{1lbf}{32.2\frac{lbm*ft}{s^2}}=2.21lbf$
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