Answer
$ x=1$ , $y=1$ and $ z=0$
Work Step by Step
Use EES Software
Enter the equations in EES
$x^2y-z=1 $
$ x-3y^(0.5)+xz=-2 $
$ x+y-z=2$
We will get
$ x=1$ , $y=1$ and $ z=0$
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