Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 45: 1-73

Answer

$P=555.69kPa$

Work Step by Step

Knowing that $P=P_{atm}+\rho*g*h$ $P=101000Pa+(1.03*1000\frac{kg}{m^3})*(9.81\frac{m}{s^2})*(45m)$ $P=555.69kPa$
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