Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 45: 1-72

Answer

$h_{blood}=1.55m$

Work Step by Step

Knowing that: $P=\rho*g*h$ $P_{high}=(13600\frac{kg}{m^3})*(9.81\frac{m}{s^2})*(0.12)=16009.92Pa$ $h_{blood}=\frac{P_{high}}{g*\rho_{blood}}=\frac{16009.92Pa}{(9.81\frac{m}{s^2})*(1050\frac{kg}{m^3})}$ $h_{blood}=1.55m$
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