Answer
$A=1.37m^2$
Work Step by Step
First we calculated the force exerted by its weight:
$W=mg=70kg*9.81\frac{m}{s^2}=686.7N$
Then the minimum area needed is:
$A=\frac{W}{P}=\frac{686.7N}{500Pa}=1.37m^2$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 1 - Introduction and Basic Concepts - Problems - Page 43: 1-56
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