Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 43: 1-38E

Answer

$-40^{\circ}C = -40^{\circ}F = 233.15K = 419.67R$

Work Step by Step

$T(^{\circ}F) = (-40^{\circ}C)(1.8) + 32 = -40^{\circ}F$ $T(K) = -40^{\circ}C + 273.15 = 233.15K$ $T(R) = -40^{\circ}F + 459.67 = 419.67R$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.