Answer
(a) $v_x=7.92m/s$
(b) $v_y=4.6m/s$
(c) $\theta=30.15^{\circ}$
Work Step by Step
(a) We know that
$v_x=v_{\circ x}+a_xt$
We plug in the known values to obtain;
$v_x=0+(11m/s^2)(0.72s)$
$v_x=7.92m/s$
(b) We can find the y-component of the hummingbird's velocity as
$v_y=v_{\circ y}+a_yt$
We plug in the known values to obtain:
$v_y=4.6m/s+(0)t$
$v_y=4.6m/s$
(c) We can find the required direction as follows:
$\theta=tan^{-1}(\frac{v_y}{v_x})$
We plug in the known values to obtain:
$\theta=tan^{-1}(\frac{4.6m/s}{7.92m/s})$
$\theta=tan^{-1}(0.581)$
$\theta=30.15^{\circ}$
