Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 108: 61

(a) $64^{\circ}$ west of north. (b) $350m$

(a) We know that $v_y=\frac{Y}{t}$ We plug in the known values to obtain: $v_y=\frac{170}{12}=14\frac{m}{s}$ Now $cos\theta=\frac{v_y}{v}$ $\implies \theta=cos^{-1}(\frac{14}{32})$ $\theta=64^{\circ}$ west of north. (b) We know that $\tan\theta=\frac{x}{y}$ $\implies x=ytan\theta$ $x=170tan64^{\circ}$ $x=350m$